Sunday, 19 September 2010

Continue with label demo

 test:
        for (int i = 0; i <= max; i++) {
            int n = substring.length();
            int j = i;
            int k = 0;
            while (n-- != 0) {
                if (searchMe.charAt(j++!= substring.charAt(k++)) {
                    continue test;
                }
            }    
            foundIt = true;
            break test;
        }

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