Playing with double datatype using Java

Do you guess the output values of the following code snippets (in  Java) ? .

                        double d5 =99999.99;
                        double d6 =999999.99;
                        double d7 =9999999.99;
                        double d8 =99999999.99;
                        double d9 =999999999.99;
                        double d10=9999999999.99;

                        System.out.println("d5 ="+d5);
                        System.out.println("d6 ="+d6);
                        System.out.println("d7 ="+d7);
                        System.out.println("d8 ="+d8);
                        System.out.println("d9 ="+d9);
                        System.out.println("d10="+d10);

Here is the output:

d5 =99999.99
d6 =999999.99
d7 =9999999.99
d8 =9.999999999E7
d9 =9.9999999999E8
d10=9.99999999999E9

Have you noticed the values of d8, d9 and d10?. The output value is in  E (exponential) format. Java is internally doing this conversion while convert the datatype double to String.  If the value is  greater than or equal to 10^-3 but less than 10⁷, then the output will be normal. Otherwise the value will be in Exponential.

To print the values all in normal format, use the "java.text.DecimalFormat" class. Check the following code snippet.

                        DecimalFormat d = new DecimalFormat("##.##");
                        System.out.println("d5 ="+d.format(d5));
                        System.out.println("d6 ="+d.format(d6));
                        System.out.println("d7 ="+d.format(d7));
                        System.out.println("d8 ="+d.format(d8));
                        System.out.println("d9 ="+d.format(d9));
                        System.out.println("d10="+d.format(d10));

The output is

d5 =99999.99
d6 =999999.99
d7 =9999999.99
d8 =99999999.99
d9 =999999999.99
d10=9999999999.99

Refer the following URL to get the more details about the Double,.

• http://download.oracle.com/javase/6/docs/api/java/lang/Double.html#toString(double)

Divide by Zero in case of Java

One of the good interview questions I found was related to divide by zero.
Lets take the case:

What will be the output of this code snippet?

public class NaN {
 
    public static void main(String[] args) {
        double d = 2.0 / 0.0;
        System.out.println(d);
    }
}

What's the answer: The code will not compile or will it throw a DivideByZero error? Both are wrong. The code compiles fine and the output is,

Infinity

Let's check another code snippet,

public class NaN {
 
    public static void main(String[] args) {
        double d = 0.0 / 0.0;
        System.out.println(d);
    }
}

The output in this case is,

NaN

Java: Rounding off to 2 decimal places

Seeking the simplest way to round off a float value to 2 decimal places, i found these:

Method 1:
x = (double)int((x+0.005)*100.0)/100.0;

Method 2:
x = Math.round(x*100.0) / 100.0;

Method 3:
DecimalFormat df2 = new DecimalFormat( "#,###,###,##0.00" );
double dd = 100.2397;
double dd2dec = new Double(df2.format(dd)).doubleValue();

Method 4:
f = (float) (Math.round(n*100.0f)/100.0f);

Method 5:
double r = 5.1234;
System.out.println(r); // r is 5.1234
int decimalPlaces = 2;
BigDecimal bd = new BigDecimal(r);
bd = bd.setScale(decimalPlaces, BigDecimal.ROUND_HALF_UP); // setScale is immutable
r = bd.doubleValue();
System.out.println(r); // r is 5.12

[source: www.thescripts.com, accuracy unchecked]

How I did it:
float percentage = score.floatValue()/(qapairs.length*10)*100; //my float value
percentage = Float.valueOf((new DecimalFormat("###.00").format(percentage)));